Control Valve (Metric Units)

Control Valve (English Units)

Summary

This example will walk you through a simple calculation to calculate a pipe size for a system with a control valve.

Topics Covered

  • Using flow control valves

  • Entering and changing pipe size data

  • Adding items to the output using Output Control

  • Modifying output using Output Control

Required Knowledge

This example assumes the user has already worked through the Beginner - Air Heating System example, or has a level of knowledge consistent with that topic.  You can also watch the AFT Arrow Quick Start Video on the AFT website, as it covers the majority of the topics discussed in the Beginner: Air Heating System example.

Model File

This example uses the following file, which is installed in the Examples folder as part of the AFT Arrow installation:

Problem Statement

For this problem, steam flows from one tank to another. The pipe between the tanks is horizontal, and 140 meters long. A control valve is used to control the flow. The control valve must have a pressure drop of at least 1.5 bar (150 kPa) to operate correctly. Assume the control valve is in the middle of the pipe. The ambient temperature is 15 deg. C. The pipe has an ambient air velocity of 25 km/hr, and no insulation. The inlet stagnation pressure and temperature values are 16 barG (1600 kPa(g)) and 220 deg. C, and the outlet stagnation pressure and temperature values are 9 barG (900 kPa(g)) and 220 deg. C. Note that the discharge temperature does not have an impact on calculations unless the discharge boundary happens to be supplying flow. Therefore, an assumed temperature can be used.

The pipe must be sized correctly to allow 2 kg/sec to flow from one reservoir to the other. Consider only STD (schedule 40) pipes.

Step 1. Start AFT Arrow

From the Start Menu choose the AFT Arrow 10 folder and select AFT Arrow 10.

To ensure that your results are the same as those presented in this documentation, this example should be run using all default AFT Arrow settings, unless you are specifically instructed to do otherwise.

Step 2. Define the Fluid Properties Group

  1. Navigate to the Fluid panel in Analysis Setup

  2. Define the Fluid panel with the following inputs

    1. Fluid Library = AFT Standard

    2. Fluid = Steam

      1. After selecting, click Add to Model

    3. Equation of State = Redlich-Kwong

    4. Enthalpy Model = Generalized

    5. Specific Heat Ratio Source = Library

Step 3. Define the Pipes and Junctions Group

At this point, the first two groups are completed in Analysis Setup. The next undefined group is the Pipes and Junctions group. To define this group, the model needs to be assembled with all pipes and junctions fully defined. Click OK to save and exit Analysis Setup then assemble the model on the workspace as shown in the figure below.

Figure 1: Workspace window showing the model layout for Control Valve example

The system is in place but now we need to enter the properties of the objects. Double-click each pipe and junction and enter the following properties.

For this example, you need to find the correct pipe size but you are limited to STD (schedule 40) pipe sizes. You need to use your engineering judgment to take an initial guess at the pipe size for 2 kg/sec. Try 2-½ inch pipe. Specify the pipes as follows:

Pipe Properties

  1. Pipe Model tab

    1. Pipe Material = Steel - ANSI

    2. Pipe Geometry = Cylindrical Pipe

    3. Size = 2-1/2 inch

    4. Type = STD (schedule 40)

    5. Friction Model Data Set = Standard

    6. Length = 70 meters

  2. Heat Transfer tab

    1. Heat Transfer Model = Convective Heat Transfer

    2. Temperature = 15 deg. C

    3. Fluid Velocity = 25 km/hr

    4. Fluid = Air

Figure 2: Pipe Heat Transfer Properties window

Junction Properties

  1. J1 Tank

    1. Elevation = 0 meters

    2. Fluid = Steam

    3. Pressure = 16 barG (1600 kPa(g))

    4. Temperature = 220 deg. C

  2. J2 Control Valve

    1. Elevation = 0 meters

    2. Valve Type = Flow Control (FCV)

    3. Control Setpoint = Mass Flow Rate

    4. Flow Setpoint = 2 kg/sec

    5. Always Control (Never Fail) = Unchecked

  3. J3 Tank

    1. Elevation = 0 meters

    2. Fluid = Steam

    3. Pressure = 9 barG (900 kPa(g))

    4. Temperature = 220 deg. C

ØTurn on Show Object Status from the View menu to verify if all data is entered. If so, the Pipes and Junctions group in Analysis Setup will have a check mark. If not, the uncompleted pipes or junctions will have their number shown in red. If this happens, go back to the uncompleted pipes or junctions and enter the missing data.

Step 4. Run the Model

Click Run Model on the toolbar or from the Analysis menu. This will open the Solution Progress window. This window allows you to watch as the AFT Arrow solver converges on the answer. Once the solver has converged, view the results by clicking the Output button at the bottom of the Solution Progress window.

Step 5. Specify the Output Control

Open the Output Control window by selecting Output Control from the Toolbar or Tools menu.

In this example, you want to review the effects of changing the pipe nominal size. To simplify this, add this parameter to the output.

  1. Click the Pipes button in the Display Parameters tab.

  2. In the list on the left, find the parameter Nominal Size.

  3. Select the Nominal Size parameter and then click the Add button, which adds the parameter to the list of displayed parameters on the right.

  4. Use the Reorder buttons (in the upper right) to move the Nominal Size up so that it becomes the second parameter in the list (see Figure 3).

  5. Click OK.

Figure 3: Output Control window

Step 6. Examine the Output

The Output window contains all the data that was specified in the Output Control window. The output is shown in Figure 4. In the General section of the Output window, there is a Warnings tab. Select this tab and you can see that for this case, the flow control valve was not able to achieve the required flow rate of 2 kg/sec. Even when there is no pressure loss across the control valve, the flow rate is below the setpoint, so the valve is unable to maintain control for this size of pipe.

In addition warnings are shown that the fluid is above the saturation pressure line. AFT Arrow cannot calculate the actual behavior of the gas when the saturation line is reached. Instead Arrow will extrapolate the fluid properties assuming that the fluid would remain in the gas phase, and will warn the user that the saturation line was exceeded as is seen here.

Figure 4: Output for Control Valve Example

Step 7. Size Piping Insulation

It is necessary to evaluate a new pipe size and to address the condensation warnings. Let's first address the condensation warnings, the pipe size will be addressed in the next step. We will assume that the necessary insulation thickness will not vary largely with pipe size because the expected change in pipe size should be relatively small in the next step.

One way to keep the fluid temperature above saturation and prevent condensation, would be to add insulation to the pipe. Assume there are three sizes of insulation available, 1.0 cm, 1.5 cm, and 2.0 cm thick, each of which has a thermal conductivity of 0.2 W/m-K. Assuming the same insulation for both pipes, which insulation size would be necessary to prevent condensation in the line?

Because this 2-1/2 inch model may be useful for comparison, keep this scenario by returning to the Workspace and then creating a new scenario on the Scenario Manager as a Child scenario by right-clicking on the Base Scenario and selecting Create Child. Name the child scenario 2.5 inch Pipe.

Repeat this process to create another new scenario as a child to the 2.5 inch Pipe scenario called With Insulation. Insulation is added on the Pipe Properties window's Heat Transfer tab. AFT Arrow allows you to specify up to three layers of insulation. The insulation can be specified as internal insulation, external insulation, or a combination of the two.

Add the insulation to the pipe by changing the Number of Insulation Layers to 1 External, and then add the insulation thermal data to the table (see Figure 5). For Conductivity, enter 0.2 W/m-K and for thickness, enter 1.5 cm as an initial guess. Make these changes to both pipes. Running the scenario, the insulation proves sufficient to prevent condensation in the 2.5 inch pipes, but the pipes remain too restrictive for the control valve to achieve the desired flow rate.

Figure 5: Insulation data is added on the Heat Transfer tab of the Pipe Properties window

Step 8. Change Pipe Size

Create a child scenario of the With Insulation scenario and name it 3 inch Pipe. From this scenario, select a new pipe size in the Pipe Properties window for both pipes. By trial and error, you can determine that by using 3-inch pipe, the minimum 1.5 bar (150 kPa) pressure drop requirement can be satisfied (see Valve Summary tab in Figure 6). Do the results change if the valve is not in the middle of the pipe?

Figure 6: Output results for 3 inch Nominal Pipe Size modified Control Valve Example

Conclusion

To meet the system requirements, 3-inch pipe should be used. If the valve were not in the middle of the pipe, the results would change because there is less pressure drop available as the valve is moved towards the pipe inlet. To prevent condensation in the line, the 1.5 cm thick insulation would have to be used.