Verification Case 54
PRODUCT: AFT Fathom
TITLE: FthVerify54.fth
REFERENCE: William S. Janna, Introduction to Fluid Mechanics, 1983, PWS Publishers, Page 183-186, Example 5.9
FLUID: Water
ASSUMPTIONS: Water at 77 deg. F
RESULTS:
| Parameter | Janna | AFT Fathom |
| Flow rate pipe 2 (ft3/sec) | 0.19 | 0.1947 |
| Flow rate pipe 3 (ft3/sec) | 0.11 | 0.1053 |
DISCUSSION:
The problem statement does not have any pressure information, because it is not required if the only purpose is to calculate flow rates. However, AFT Fathom requires at least one pressure boundary because AFT Fathom offers pressure information in the output for all systems. Therefore, a pressure of 1 atm was assumed for the common junction at the exit of the system.
An "out of balance" warning may appear in the AFT Fathom Output. The amount that is out of balance is very small and therefore the warning can be neglected.
