Verification Case 52
PRODUCT: AFT Fathom
TITLE: FthVerify52.fth
REFERENCE: William S. Janna, Introduction to Fluid Mechanics, 1983, PWS Publishers, Page 176-177, Example 5.6
FLUID: Turpentine
ASSUMPTIONS: Use Janna K factors
RESULTS:
Parameter | Janna | AFT Fathom |
Static Pressure difference (kPa) | 3.012 | 2.938 |
DISCUSSION:
The various pipe lengths and intermediate junction elevations are not specified by Janna, so values were assigned to the AFT Fathom model such that the total lengths of 60 m and 22 m resulted, and the endpoint elevations were correct.
Results disagree slightly because Janna reads friction factors from a chart, which is less accurate than AFT Fathom's correlation based method.
The pressure drop in AFT Fathom can be obtained by subtracting the exit pressure from the inlet in the Output window junction results table, or in the Junction Deltas table at the top of the Output window. The junction delta was created in the Output Control window.